请问 这几题怎么做 因式分解
x(x^2-xy)-(4x^2-4xy)(a^2+2ab)^2+2(a^2+2ab)b^2+b^4(x+y)^3-(x-y)^2(x+y)...
x(x^2-xy)-(4x^2-4xy) (a^2+2ab)^2+2(a^2+2ab)b^2+b^4 (x+y)^3-(x-y)^2(x+y)
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(1)原式=x^2(x-y)-4x(x-y)
=(x-y)(x^2-4x)
=x(x-y)(x-4)
(2)可以看出三个部分组成一个完全平方式,所以,
原式=(a^2+2ab+b^2)^2
=[(a+b)^2]^2
=(a+b)^4
(3)原式=(x+y)[(x+y)^2-(x-y)^2]
=(x+y)(x+y+x-y)(x+y-x+y) {此步利用了平方差公式}
=4xy(x+y)
=(x-y)(x^2-4x)
=x(x-y)(x-4)
(2)可以看出三个部分组成一个完全平方式,所以,
原式=(a^2+2ab+b^2)^2
=[(a+b)^2]^2
=(a+b)^4
(3)原式=(x+y)[(x+y)^2-(x-y)^2]
=(x+y)(x+y+x-y)(x+y-x+y) {此步利用了平方差公式}
=4xy(x+y)
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x(x²-xy)-(4x²-4xy)
=x²(x-y)-4x(x-y)
=(x-y)(x²-4x)
=x(x-y)(x-4)
(a²+2ab)²+2(a²+2ab)b²+b^4
=(a²+2ab)²+2(a²+2ab)b²+(b²)²
=(a²+2ab+b²)²
=(a+b)^4
(x+y)³-(x-y)²(x+y)=(x+y)[(x+y)²-(x-y)²]
=(x+y)(x+y+x-y)(x+y-x+y)
=4xy(x+y)
=x²(x-y)-4x(x-y)
=(x-y)(x²-4x)
=x(x-y)(x-4)
(a²+2ab)²+2(a²+2ab)b²+b^4
=(a²+2ab)²+2(a²+2ab)b²+(b²)²
=(a²+2ab+b²)²
=(a+b)^4
(x+y)³-(x-y)²(x+y)=(x+y)[(x+y)²-(x-y)²]
=(x+y)(x+y+x-y)(x+y-x+y)
=4xy(x+y)
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