若x^2 3x-1=0,则代数式x-3/(3x^2-6x)除以[x+2-5/(x-2)]的值是多少？要步骤
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x²+3x-1=0
x²+3x=1
(x-3)/(3x^2-6x)除以[x+2-5/(x-2)]
=(x-3)/3x(x-2)÷(x²-4-5)/(x-2)
=[(x-3)/3x(x-2)]*(x-2)/(x-3)(x+3)
=1/3x(x+3)
=1/3x²+9x
=1/3(x²+3x)
=1/3
x²+3x=1
(x-3)/(3x^2-6x)除以[x+2-5/(x-2)]
=(x-3)/3x(x-2)÷(x²-4-5)/(x-2)
=[(x-3)/3x(x-2)]*(x-2)/(x-3)(x+3)
=1/3x(x+3)
=1/3x²+9x
=1/3(x²+3x)
=1/3
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