Question

c语言 平面n个点坐标,计算各点间距离之和(struct coordinative)

编程 输入平面上n(3<n<=10)个点的坐标，计算各点的距离之和。
坐标点的的类型定义和相应的数组定义为：
struct cpprdinative{
float x;
float y;
}point[10];

输入输出：
n=10
63,22 56,25 50,30 42,37 53,45
60,55 70,55 76,49 80,40 72,28
Distance=1029.56

Answer 1

#include "stdio.h"
#include "math.h"
struct cpprdinative{
float x;
float y;
}point[10];
void main()
{
int n = 0;
printf("n=");scanf("%d", &n);
for(int i = 0;i < n; i ++)
{
scanf("%f,%f", &point[i].x, &point[i].y);
}
float Distance =0;
for(int i = 0; i < n; i ++)
{
for(int j = i+1; j < n;j ++)
{
Distance += sqrt((point[i].x-point[j].x)*(point[i].x-point[j].x)+ (point[i].y-point[j].y)*(point[i].y-point[j].y));
}
}
printf("Distance = %f", Distance);
}
// 输入
n=10
63,22
56,25
50,30
42,37
53,45
60,55
70,55
76,49
80,40
72,28
// 输出
Distance = 1029.568237

Answer 2

是两点间的距离还是啥