Question

帮我解一个一元一次方程

Answer 1

(1)
(2x-5)/3 - (3x-11)/4 = (1-5x)/2
4(2x-5) - 3(3x-11) = 6(1-5x)
8x-20-9x+33=6-30x
-x+13=6-30x
29x=-7
x=-7/29
(2)
16x/15 -(1-x)/6 = -(2x-1)/5 + (2x+1)/18
16x/15 +(2x-1)/5 = (2x+1)/18 +(1-x)/6
(22x-3)/15 = (-x+4)/18
(22x-3)/5 = (-x+4)/6
6(22x-3)=5(-x+4)
132x-18=-5x+20
137x = 38
x= 38/137
(3)
(1-2y)/6+(2y+1)/4 = 1- (y+1)/3
2(1-2y)+3(2y+1) = 12- 4(y+1)
2-4y+6y+3 =12-4y-4
2y+5 =-4y+8
6y=3
y=1/2