Question

麻烦学霸帮忙算一下

4x的（-5/4）次方+8x的（1/4）次方

Answer 1

(1) y = (x + m)(x - 3m) A(-m, 0), B(3m, 0), C(0, -3m2) (2) 抛物线的对称轴为x = (3m - m)/2 = m, C，D关于x = m对称, D的横坐标为2m, 坐标为(2m, -3m2) 将直线和抛物线联立: y = x + m = (x + m)(x - 3m) x - 3m = 1 (舍去x = -m, 此为A点) F(3m+1, 4m+1) AF的斜率为1, AD的斜率=(-3m2 - 0)/[[2m - (-m)] = -m = -1, m = 1 F(4, 5) (3) F(4, 5), A(-1, 0), E(1, -4) G有三种可能: (i) AF为对角线, 其中点M(3/2, 5/2)为EG的中点，令G(g, g'): (g + 1)/2 = 3/2, g = 2 (g' - 4)/2 = 5/2, g' = 9 G(2, 9) (ii) EF为对角线, 与(i)类似可得G(6, 1) (iii) AE为对角线, 此时G在第三象限，舍去