求这题不定积分
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=∫(x+1)^(1/3)/(x-1)^(1/3)(x+1)(x-1)dx
=1/2∫(x+1)^(1/3)/(x-1)^(4/3)-1/(x+1)^(2/3)(x-1)^(1/3)dx
=-3/2∫(x+1)^(1/3)d(1/(x-1)^(1/3))-3/2∫1/(x-1)^(1/3)d(x+1)^(1/3)
=(-3/2)(x+1)^(1/3)/(x-1)^(1/3)+C
=1/2∫(x+1)^(1/3)/(x-1)^(4/3)-1/(x+1)^(2/3)(x-1)^(1/3)dx
=-3/2∫(x+1)^(1/3)d(1/(x-1)^(1/3))-3/2∫1/(x-1)^(1/3)d(x+1)^(1/3)
=(-3/2)(x+1)^(1/3)/(x-1)^(1/3)+C
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