Question

C语言编写程序从键盘任意输入一个4位数X，编程计算X的每一位数字相加之和（忽略整数前的正负号）

Answer 1

#include<stdio.h>

void main()
{
int i=0,sum=0;
char s[10];
scanf("%s",s);
while(s[i]!=0)
{
if(s[i]>='0' && s[i]<='9')
sum += s[i]-'0';
i++;
}
printf("%s的每一位数字相加之和为%d\n",s,sum);
}

Answer 2

#include<stdio.h>

int main()
{
int n;
printf("please input n\n");
scanf("%d",&n);
int sum = 0;
int s;
int k = n;
while(k > 0)
{
s = k % 10;
k /= 10;
sum += s;

}
printf("%d每个位数的和为%d\n",n,sum);
return 0;
}

please input n
-1234
-1234每个位数的和为10
Press any key to continue