1.分解因式;X的平方减3XY减10Y的平方加X加9Y减2 2.分解因式;X的5次方加X加1
1个回答
展开全部
添项、拆项,得
x^2-3xy-10y^2+x+9y-2
=(x+2y)(x-5y)+2x+4y-x+5y-2
=(x+2y)(x-5y)+2(x+2y)-(x-5y+2)
=(x+2y)(x-5y+2)-(x-5y+2)
=(x+2y-1)(x-5y+2)
x^5+x+1
=x^5-x^2+x^2+x+1
=x^2(x^3-1)+(x^2+x+1)
=x^2(x-1)(x^2+x+1)+(x^2+x+1)
=(x^3-x^2)(x^2+x+1)+(x^2+x+1)
=(x^3-x^2+1)(x^2+x+1)
x^2-3xy-10y^2+x+9y-2
=(x+2y)(x-5y)+2x+4y-x+5y-2
=(x+2y)(x-5y)+2(x+2y)-(x-5y+2)
=(x+2y)(x-5y+2)-(x-5y+2)
=(x+2y-1)(x-5y+2)
x^5+x+1
=x^5-x^2+x^2+x+1
=x^2(x^3-1)+(x^2+x+1)
=x^2(x-1)(x^2+x+1)+(x^2+x+1)
=(x^3-x^2)(x^2+x+1)+(x^2+x+1)
=(x^3-x^2+1)(x^2+x+1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询