Question

编程序求 s=1/1+1/2+1/3+1/4+………+1/n

Answer 1

#include <stdio.h>
void main()
{
int i,n;
double s=0;
printf("请输入n: ");
scanf("%d",&n);
for(i=1;i<=n;i++)
s+=1.0/i;
printf("%g\n",s);
}

Answer 2

int main(void)
{
double sum = 0;
double e = 1e-6; //控制精度.
for(double index = 1;;1/index > e;++index)
{
sum += 1/index;
}
printf("the result is: %g",sum);
system("pause");
return EXIT_SUCCESS;
}

不知道题干中的n是手动输入的还是怎样，我就当你是求1/1+1/2+...+1/n+...。