高数问题求解‼lim(tanx-sinx)/(sinx)^3 .x趋向0
1个回答
展开全部
lim(x→0) (tanx - sinx)/(sinx)^3
= lim(x→0) (tanx - sinx)/x^3,分母等价无穷小
= lim(x→0) sinx(1/cosx - 1)/x^3
= lim(x→0) (sinx)/x * (1 - cosx)/(x^2 * cosx)
= lim(x→0) 2[sin(x/2)]^2/x^2
= lim(x→0) [sin(x/2)]^2/(x/2)^2 * 1/2
= 1/2
= lim(x→0) (tanx - sinx)/x^3,分母等价无穷小
= lim(x→0) sinx(1/cosx - 1)/x^3
= lim(x→0) (sinx)/x * (1 - cosx)/(x^2 * cosx)
= lim(x→0) 2[sin(x/2)]^2/x^2
= lim(x→0) [sin(x/2)]^2/(x/2)^2 * 1/2
= 1/2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询