Question

f(x，y)=xeˣʸ+y,求对x的偏导

Answer 1

f(x,y) =xe^(xy) + y
对x的偏导
fx(x,y)
=∂/∂x [xe^(xy) + y]
=e^(xy). ∂/∂x(x) + x∂/∂x(e^(xy)) +0
=e^(xy). (1) + x.(e^(xy)) .∂/∂x(xy)
=e^(xy) + x.(e^(xy)) .(y)
=(1+xy)e^(xy)