Question

化简3ab(a^2b-ab^2+ab)-ab^2(2a^2-3ab+2a)

Answer 1

3ab(a^2b-ab^2+ab)-ab^2(2a^2-3ab+2a)
=3a^2b^2(a-b+1)-a^2b^2(2a-3b+2)
=a^2b^2(3a-3b+3)-a^2b^2(2a-3b+2)
=a^2b^2(3a-3b+3-2a+3b-2)
=a^2b^2(a+1)

Answer 2

3ab(a^2b-ab^2+ab)-ab^2(2a^2-3ab+2a)
=3a^3b^2-3a^2b^3+3a^2b^2-2a^3b^2+3a^2b^3-2a^2b^2
=a^3b^2+a^2b^2