用递等式计算(能简算的要用简便方法计算).?
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解题思路:算式(1)可以根据加法交换律进行计算;
算式(2)可以根据乘法分配律进行计算;
其余算式根据四则混合运算的运算法则计算即可:选算乘除,再算加减,有括号的要先算括号里面的.
(1)4.32+3.2+5.68
=4.32+5.68+3.2,
=10+3.2,
=13.2;
(2)79×101-79
=(101-1)×79,
=100×79,
=7900;
(3)132+25×8
=132+200,
=332;
(4)20-[3/25]×5
=20-[3/5],
=19[2/5];
(5)(0.125×8-0.5)×4
=(1-0.5)×4,
=0.5×4,
=2;
(6)(0.25+[5/8])÷([7/4]-[7/8])
=([2/8]+[5/8])÷([14/8−
7
8]),
=[7/8÷
7
8],
=1.
,6,用递等式计算(能简算的要用简便方法计算).
4.32+3.2+5.68
79×101-79
132+25×8
20-[3/25]×5
(0.125×8-0.5)×4
(0.25+[5/8])÷([7/4]-[7/8])
算式(2)可以根据乘法分配律进行计算;
其余算式根据四则混合运算的运算法则计算即可:选算乘除,再算加减,有括号的要先算括号里面的.
(1)4.32+3.2+5.68
=4.32+5.68+3.2,
=10+3.2,
=13.2;
(2)79×101-79
=(101-1)×79,
=100×79,
=7900;
(3)132+25×8
=132+200,
=332;
(4)20-[3/25]×5
=20-[3/5],
=19[2/5];
(5)(0.125×8-0.5)×4
=(1-0.5)×4,
=0.5×4,
=2;
(6)(0.25+[5/8])÷([7/4]-[7/8])
=([2/8]+[5/8])÷([14/8−
7
8]),
=[7/8÷
7
8],
=1.
,6,用递等式计算(能简算的要用简便方法计算).
4.32+3.2+5.68
79×101-79
132+25×8
20-[3/25]×5
(0.125×8-0.5)×4
(0.25+[5/8])÷([7/4]-[7/8])
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