Question

分解因式，写过程，谢谢

(a的平方-b的平方)的平方+4a的平方b的平方 (36分之一a减三分之一)a+1 2（a-1）的2次方-12（a-1)+18 （x的平方-2xy+y的平方）+(-2x+2y) +1

Answer 1

(a^2-b^2)^2+4a^2b^2=a^4-2a^2b^2+b^4+4a^2b^2
=a^4+2a^2b^2+b^4=(a^2+b^2)^2

(a/36一1/3)a+1=(a^2-12a+36)/36=(1/36)(a-6)^2

2（a-1)^2-12（a-1)+18 =2(a-1-3)^2=2(a-4)^2

（x^2-2xy+y^2）+(-2x+2y) +1
=(x-y)^2-(x-y)+1=(x-y-1)^2

Answer 2

1.(a^2-b^2)^2+4a^2b^2=(a^2+b^2)^2
2.(a/36-1/3)a+1=a^2/36-a/3+1=(a/6-1)^2
3.2(a-1)^2-12(a-1)+18=2(a-1-3)^2=2(a-4)^2
4.(x^2-2xy+y^2)+(-2x+2y)+1=(x-y)^2-2(x-y)+1=(x-y-1)^2