Question

高数！谢谢！设z=e^(x-2y)，而x=sint，y=t^3，求dz/dt

Answer 1

z=e^(x-2y)=e^[sint-2*t^3]
dz/dt=
e^[sint-2*t^3] * (cost-6*t^2)

Answer 2

z=e^(x-2y)
=e^(sint-2t^3)
dz/dt= [cost-6t^2].e^(sint-2t^3)

追问

http://zhidao.baidu.com/question/442872353.html?quesup2&oldq=1，http://zhidao.baidu.com/question/442868047.html?quesup2&oldq=1，http://zhidao.baidu.com/question/442858230.html?quesup2&oldq=1，谢谢！帮忙看下好吗！