Question

-t平方加2t加3乘以3减去-7平方加2t加3的和？

Answer 1

解方程：
(-t²+2t+3)/(t-2) = (t+1)/[3-(-t²+2t+3)]
∵ -t²+2t+3 = -(t-3)(t+1)
3-(-t²+2t+3) = t²-2t = t(t-2)
∴原方程可简化为
-(t-3) = 1/t
t²-3t+1 = 0
Δ=(-3)²-4 = 5
t = (3±√5)/2