解不等式3x-5/x²+2x-3≤2
1个回答
展开全部
3x-5/x²+2x-3≤2
(3x-5)/(x²+2x-3)-2(x²+2x-3)/(x²+2x-3)≤0
(3x-5-2x²-4x+6)/(x²+2x-3)<=0
(-2x²-x+1)/(x²+2x-3)<=0
(2x²+x-1)/(x²+2x-3)>=0
(x+1)(2x-1)/(x+3)(x-1)>=0
即返游激
(x+3)(x+1)(2x-1)(x-1)>=0
(x+3)(x-1)≠磨昌0
所以
x>1或-1<漏袜=x<=1/2或x<-3
(3x-5)/(x²+2x-3)-2(x²+2x-3)/(x²+2x-3)≤0
(3x-5-2x²-4x+6)/(x²+2x-3)<=0
(-2x²-x+1)/(x²+2x-3)<=0
(2x²+x-1)/(x²+2x-3)>=0
(x+1)(2x-1)/(x+3)(x-1)>=0
即返游激
(x+3)(x+1)(2x-1)(x-1)>=0
(x+3)(x-1)≠磨昌0
所以
x>1或-1<漏袜=x<=1/2或x<-3
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
