Question

求关于函数f(x)=4sin(2x+π/3) (x∈R）图像中的一条对称轴

A π/3
B π/4
C x=-π/6
D x=π/12
要详细的过程。过程

Answer 1

2x+π/3=π/2+kπ
所以2x=π/6+kπ
x=π/12+kπ/2 k属于z
所以选d

追问

x=π/12+kπ/2 k属于z
please tell me why?

追答

it is very diffical to tell you why
这是对称轴x=π/2+kπ
所以2x=π/6+kπ
x=π/12+kπ/2 k属于z

追问

额……………………

Answer 2

是以2π为最小正周期的周期函数③函数y=f(x)的图像关于点(-π/6,0)(-π/6,0)满足条件 4 f(x)=4sin(2x+π/3)的对称直线满足 2x+π/3

Answer 3

D 因为方程sin x 对称轴为兀｜2＋k兀,所以2x＋3∣兀＝兀∣2＋k兀 解得x＝兀∣12＋k兀∣20 当k＝0，x＝兀∣12