Question

遍历json集合

[{"list":[{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":"","createUserId":"","createUserName":"","deleteFlag":"0","introduction":"","month":"","pagerSize":0,"periodicalId":"","periodicalName":"admin","periodicalType":"","publishDate":null,"status":"0","updateUserDept":"","updateUserDeptId":"","updateUserId":"","updateUserName":"","year":""},{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":"","createUserId":"","createUserName":"","deleteFlag":"0","introduction":"","month":"","pagerSize":0,"periodicalId":"","periodicalName":"admin","periodicalType":"","publishDate":null,"status":"0","updateUserDept":"","updateUserDeptId":"","updateUserId":"","updateUserName":"","year":""}],"pageString":""}]

可追加分，如何遍历上面json对象

Answer 1

var a=[{"list":[{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":"","createUserId":"","createUserName":"","deleteFlag":"0","introduction":"","month":"","pagerSize":0,"periodicalId":"","periodicalName":"admin","periodicalType":"","publishDate":null,"status":"0","updateUserDept":"","updateUserDeptId":"","updateUserId":"","updateUserName":"","year":""},{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":"","createUserId":"","createUserName":"","deleteFlag":"0","introduction":"","month":"","pagerSize":0,"periodicalId":"","periodicalName":"admin","periodicalType":"","publishDate":null,"status":"0","updateUserDept":"","updateUserDeptId":"","updateUserId":"","updateUserName":"","year":""}],"pageString":""}]
var list=a[0].list;
for(i=0;i<list.length;i++){
alert(list[i].count);
alert(list[i].createTime);
............
............
............
}
当数组处理，只是成员为对象

追问

你好：那我从后台返回到页面的值还可以是json对象吗

追答

可以的，你在转到前台过程中 进行stringbuff拼接，到前台 JS遍历一样；
过程只是字符串的传递；

Answer 2

list中包含一个数组，在那对中括号里每对大括号包裹的就是数组中的一个元素，楼主可以将这个json字符串理解为有两个节点，第一个是list(内容是数组)，第二个是pageString

Answer 3

var json={
"list":[
{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":""},
{"count":0,"createTime":"2008-01-25 00:00:00","createUserDept":"","createUserDeptId":""}
],
"pageString":""
};
//traverse
for (var key in json)
{
for (var option in json[key])
{
document.write(json[key][i].count);
}
}

Answer 4

。。。。