Question

在c51编程中怎样把4个字节的数合并到一块转换成十进制数显示在液晶显示器上

Answer 1

#define uchar unsigned char

#define ulong unsigned long

定义一个联合

union Long_Byte // 长整数(4字节)
{
ulong lword;
struct
{
uchar hhi;
uchar hlo;

uchar hi;
uchar lo;
}
bytes;

};
union Long_Byte num;
ulong idata count;

// 下面就是操作了 ADDRESS2为4个字节数据地址

num.bytes.hhi=ADDRESS2+1;
num.bytes.hlo=ADDRESS2+2;
num.bytes.hi = ADDRESS2+3;
num.bytes.lo = ADDRESS2+4;
count=num.lword; // count 和 num 都是4字节数据