Question

PHP：急！急！这个问题怎么解决：Warning: Invalid argument supplied for foreach() in 。。。？

<?php
foreach($M_layout as $layout){
?>
<tr>
<td align="left"><input id="ids" type="checkbox" value="<?php echo $layout['msglaotid']?>" name="ids_[]"></input></td>
<td></td>
<td align="left"><?php echo $layout['msgtpname']?></td>
<td align="left"><?php echo $layout['sentence']?></td>
<td align="left"><?php
switch ($layout['msgisused']){
case "0": echo "未启用"; break;
case "1": echo "启用"; break;
}
?>
</td>
<td align="left"><?php echo $layout['userIdent']?></td>
<td align="left"><?php echo $layout['userName']?></td>
<td align="left">
<a class="editmessagedialog" href="###" _id="<?php echo $layout['msglaotid']?>">[修改]</a>
</td>
</tr>
<?php }?>

给加上
<?php
if(is_array($M_layout)){
?>
或者
<?php
foreach(array（$M_layout） as $layout){
?>
问题解决了，可是查不到数据。。。
SQL语句正确，在数据库里执行没有问题，能查到，在页面就查不到了

Answer 1

if(is_array($M_layout ) && !empty($M_layout )){
foreach($M_layout as $layout){

}
}
加个判断语句

Answer 2

<? while($row=mysql_fetch_array){
foreach($M_layout as $layout){
?>
<tr>
<td align="left"><input id="ids" type="checkbox" value="<?php echo $layout['msglaotid']?>" name="ids_[]"></input></td>
<td></td>
<td align="left"><?php echo $layout['msgtpname']?></td>
<td align="left"><?php echo $layout['sentence']?></td>
<td align="left"><?php
switch ($layout['msgisused']){
case "0": echo "未启用"; break;
case "1": echo "启用"; break;
}
?>

<?
}
?>

Answer 3

编码问题吧 请检查php页面编码和数据库编码是否一致

Answer 4

$M_layout没有初始化！