Question

4(m+n)²-(m-n)²怎么分解公因式

Answer 1

4(m+n)²-(m-n)²=(2m+2n+m+n)*(2m+2n-m+n)=(3m+3n)*(m+3n)

Answer 2

4(m+n)²-(m-n)²=4m²+4n²+8mn-m²-n²+2mn
=3m²+3n²+10mn
=(3m+n)(m+3n)

Answer 3

...=[2(m+n)]²-(m-n)²
=[2(m+n)+(m-n)][2(m+n)-(m-n)]
=(3m+n)(m+3n)

Answer 4

=[2（m+n)]2-(m-n)2
=[2m+2n+m-n][2m+2n-m+n]
=(3m+n)(m+3n)

Answer 5

4(m+n)²-(m-n)²=[2(m+n)+(m-n)]*[2(m+n)-(m-n)]=(3m+n)*(m+3n)=3m²+10mn+3n²