Question

跪求以下两化学题答案，急！！！大概是高一的，最好解答过程详细，谢谢啦!

1.标准状况下，取11.2LNH3溶于1000g水中，得密度为ρ g/cm³的氨水，求C（NH3）=__________
2.已知98%的浓硫酸密度1.84g/cm³，求C（H2SO4）=____________

Answer 1

解:n=11.2L/22.4L/mol=0.5mol
溶液质量0.5mol*17g/mol+1000g=1008.5g
溶液的体积为1008.5g/ρ g/cm³*=1008.5pcm³=1.0085pL
C(NH3)=0.5mol/1.0085pL=1/2pmol/L
C（H2SO4）=(1000*1.84g/cm3*98%)/(98g/mol)=18.4mol/L
答:C（NH3）=__1/2pmol/L________
C（H2SO4）=____18.4mol/L________

Answer 2

n(NH3)=11.2/22.4=0.5mol；m(NH3)=0.5*17=8.5g；m(溶液)=1000+8.5=1008.5g
V(溶液)=1008.5/ρ mL=1.0085ρL；c(NH3)=n/V=0.5/1.0085ρ ol/L

18.4mol/L