Question

jquery easyui 里面的datagrid属性showFooter设置true,为何没为有效果?

Answer 1

你的json返回内容是什么?

你的json内容中一定是缺少了footer属性，例如

{"total":5,"rows":[
{"productid":"FI-SW-01","unitcost":10.00,"status":"P","listprice":36.50,"attr1":"Large","itemid":"EST-1"},
{"productid":"K9-DL-01","unitcost":12.00,"status":"P","listprice":18.50,"attr1":"Spotted Adult Female","itemid":"EST-10"},
{"productid":"RP-SN-01","unitcost":12.00,"status":"P","listprice":28.50,"attr1":"Venomless","itemid":"EST-11"}
],"footer":[
{"unitcost":19.80,"listprice":60.40,"productid":"Average:"},
{"unitcost":198.00,"listprice":604.00,"productid":"Total:"}
]}

你缺少的应该是上面json中的"footer"这部分内容。

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Answer 2

不知道