Question

f(x)为二次函数且f(0)=3,f(x+2)-f(x)=4x+2

Answer 1

设f(x) = ax² + bx + c
f(0) = 3，代入
c = 3
f(x + 2) - f(x) = 4x + 2
f(- 2 + 2) - f(- 2) = 4(- 2) + 2
3 - f(- 2) = - 6
f(- 2) = 9，代入
9 = 4a - 2b + 3 ==> 4a - 2b = 6
f(- 4 + 2) - f(- 4) = 4(- 4) + 2
9 - f(- 4) = - 14
f(- 4) = 23，代入
23 = 16a - 4b + 3 ==> 4a - b = 5
(4a - 2b) - 2(4a - b) = 6 - 2(5)
- 4a = - 4 ==> a = 1
b = 4(1) - 5 = - 1
所以f(x) = x² - x + 3

Answer 2

由题意得c=0
x=0代入原式，得4a+2b=2
再把x=1代入原式，得8a+2b=6
联立两个等式，得a=1，b=-1
则f(x) = x² - x + 3

Answer 3

x2-x+3