Question

解方程：1/2[x-1/2(x-1)]=2/3(x-1) 求过程 （2y-1）/3=（y+2）/4-1

Answer 1

解： 1/2x-1/4(x-1)=2/3(x-1)
1/2x-[(1/4+2/3)(x-1)]=0
1/2x-11/12(x-1)=0
-5/12x=-11/12
x=11/5

Answer 2

x-1/2(x-1)=4/3(x-1)
6x-3(x-1)=8(x-1)
6x-3x-8x=-8-3
-5x==11
x=11/5

4(2y-1)=3(y+2)-12
8y-3y=6-12+4
5y=-2
y=-2/5

Answer 3

x-1/2(x-1)=4/3(x-1)
6x-3(x-1)=8(x-1)
6x-3x-8x=-8-3
-5x==11
x=11/5

4(2y-1)=3(y+2)-12
8y-3y=6-12+4
5y=-2
y=-2/5