已知x为整数,且2/x+2+2/2-x+2x+12/x2-4的值为整数,则符合条件的x有几个 20
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2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)
=(2x-4-2x-4+2x+12)/(x²-4)
=(2x+4)/(x²-4)
=2/(x-2)
则可知2/(x-2)的值为整数且x≠2,x≠-2
而x是整数,那么满足题意的x的值有:
x=4,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=1;
x=3,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=2;
x=1,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=-2;
x=0,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=-1。
=(2x-4-2x-4+2x+12)/(x²-4)
=(2x+4)/(x²-4)
=2/(x-2)
则可知2/(x-2)的值为整数且x≠2,x≠-2
而x是整数,那么满足题意的x的值有:
x=4,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=1;
x=3,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=2;
x=1,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=-2;
x=0,此时2/(x+2) + 2 /(2-x) + (2x+12)/(x²-4)=2/(x-2)=-1。
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