求化简过程,详细点,谢谢。 60
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= 2(X-2)[(X +1)^ 2/3 1/3(X-2),(X +1)^ -1 / 3]
= 2(X-2)[( X +1)^ 2/3 1/3(X-2)*(X +1)^ -1 * [(X +1)^ 2/3]
= 2(X-2)* (X +1)^ 2/3 * [1 +1 / 3(X-2)*(X +1)^ -1]
= 2(X-2)* [(X +1)^ 2/3] [1 +(X-2)/ 3(X +1)]
= 2(X-2)* [(X +1)^ 2/2] [(4×1)/ 3(X +1)]
= 2/3(X-2)* [(X +1)^ 2/3] [4×1)/(X +1)]
= 2 / 3(X-2)*(X +1)^ 2/3 *(4×1)*(X +1)^ -1
= 2/3(X-2)*(X +1 )^ 2/3 *)*(X +1)^ -1 *(4×1)
= 2/3(X-2)*(X +1)^ -1 / 3 *(4倍+ 1)
= 2/3(X-2)*(X +1)^ -1 / 3 * 4(X +1 / 4)
= 8/3 * [(X-2)的(X +1 / 4)] /(X +1)^ 1/3的
= 2(X-2)[( X +1)^ 2/3 1/3(X-2)*(X +1)^ -1 * [(X +1)^ 2/3]
= 2(X-2)* (X +1)^ 2/3 * [1 +1 / 3(X-2)*(X +1)^ -1]
= 2(X-2)* [(X +1)^ 2/3] [1 +(X-2)/ 3(X +1)]
= 2(X-2)* [(X +1)^ 2/2] [(4×1)/ 3(X +1)]
= 2/3(X-2)* [(X +1)^ 2/3] [4×1)/(X +1)]
= 2 / 3(X-2)*(X +1)^ 2/3 *(4×1)*(X +1)^ -1
= 2/3(X-2)*(X +1 )^ 2/3 *)*(X +1)^ -1 *(4×1)
= 2/3(X-2)*(X +1)^ -1 / 3 *(4倍+ 1)
= 2/3(X-2)*(X +1)^ -1 / 3 * 4(X +1 / 4)
= 8/3 * [(X-2)的(X +1 / 4)] /(X +1)^ 1/3的
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