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∫[(x-5)/(x^3-3x^2+4)]dx
=∫[(x-5)(x^3+x^2-4x^2+4)]dx
=∫{(x-5)/[x^2(x+1)-4(x^2-1)]}dx
=∫{(x-5)/[(x+1)(x^2-4x+4)]}dx
=∫{(x-5)/[(x+1)(x-2)^2]}dx
=∫{[2(x-2)-(x+1)]/[(x+1)(x-2)^2]}dx
=2∫{1/[(x+1)(x-2)]}dx-∫[1/(x-2)^2]dx
=(2/3)∫[1/(x-2)-1/(x+1)]dx-∫[1/(x-2)^2]d(x-2)
=(2/3)ln|x-2|-(2/3)ln|x+1|+1/(x-2)+C
=∫[(x-5)(x^3+x^2-4x^2+4)]dx
=∫{(x-5)/[x^2(x+1)-4(x^2-1)]}dx
=∫{(x-5)/[(x+1)(x^2-4x+4)]}dx
=∫{(x-5)/[(x+1)(x-2)^2]}dx
=∫{[2(x-2)-(x+1)]/[(x+1)(x-2)^2]}dx
=2∫{1/[(x+1)(x-2)]}dx-∫[1/(x-2)^2]dx
=(2/3)∫[1/(x-2)-1/(x+1)]dx-∫[1/(x-2)^2]d(x-2)
=(2/3)ln|x-2|-(2/3)ln|x+1|+1/(x-2)+C
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