Tn=1×(1/3)¹+ 2×(1/3)²+。。。+n×(1/3)∧n-(1+2+3+。。。n) 1/3Tn=1×(1/3 )²+2×(1/3)³+。。。n×(1/3)∧(n+1)-n(1+2+3+。。。+n ) Tn-1/3Tn=(1/3)¹+(1/3)²+(1/3)³+。。。+(1/3)∧n-n×(1/3)∧(n+1)-(n-1 )(1+2+3+。。。+n)=2/3Tn Tn=1/2-1/2×1/3∧n+3/2n×(1/3)∧n-(n³-n)×3/4 不知道打成这样你看不看的懂,结果你要验算一下,我可能会算错,但思路还是对的