Question

。net从字符串取出十六进制字符并且把它转为二进制

两个十六进制数转换成8位二进制

Answer 1

你说的是转为byte数组吧

private static byte[] ToHexByte(string hexString)
{
hexString = hexString.Replace(" ", "");
if ((hexString.Length % 2) != 0)
hexString += " ";
byte[] returnBytes = new byte[hexString.Length / 2];
for (int i = 0; i < returnBytes.Length; i++)
returnBytes[i] = Convert.ToByte(hexString.Substring(i * 2, 2), 16);
return returnBytes;
}

追问

我说的是二进制数，不是byte数组，请问该如何转化

追答

static string ToBinString(string s)
{
Func toByte = (char1) => {
if (char1 >= '0' && char1 = 'A' && char1 = 'a' && char1 toBin = (byte1) =>
string.Format("{0}{1}{2}{3}",
byte1 >> 0 & 0x1,
byte1 >> 1 & 0x1,
byte1 >> 2 & 0x1,
byte1 >> 3 & 0x1
);

string result = "";
foreach (var char1 in s)
{
var b = toByte(char1);
result += toBin(b);
}
return result;
}

Answer 2

int intValue = Convert.ToInt32(value, 16);

return Convert.ToString(intValue, 2);