Servlet获取客户端IP地址不正确
servlet代码如下，在浏览器输出显示为：为什么不对呢？我的系统和编程环境如下：系统：Win764位。MyEclipse6.5,32位。Tomcat6.0.35，64位...
servlet代码如下，在浏览器输出显示为：
为什么不对呢？我的系统和编程环境如下：
系统：Win7 64位。
MyEclipse 6.5,32位。
Tomcat 6.0.35，64位
JDK jdk1.7.0_05，64位
Servlet代码：
package com.javaWeb.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class IpServlet extends HttpServlet {
public String getRemoteAddress(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getRemoteAddr();
}
return ip;
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
this.doPost(request, response);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String ip = getRemoteAddress(request);
response.setCharacterEncoding("UTF-8");
request.setCharacterEncoding("UTF-8");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.println("您的IP地址为：<b>"+ip+"</b><br/>");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
} 展开
为什么不对呢？我的系统和编程环境如下：
系统：Win7 64位。
MyEclipse 6.5,32位。
Tomcat 6.0.35，64位
JDK jdk1.7.0_05，64位
Servlet代码：
package com.javaWeb.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class IpServlet extends HttpServlet {
public String getRemoteAddress(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getHeader("Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if (ip == null || ip.length() == 0 || ip.equalsIgnoreCase("unknown")) {
ip = request.getRemoteAddr();
}
return ip;
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
this.doPost(request, response);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String ip = getRemoteAddress(request);
response.setCharacterEncoding("UTF-8");
request.setCharacterEncoding("UTF-8");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\">");
out.println("<HTML>");
out.println(" <HEAD><TITLE>A Servlet</TITLE></HEAD>");
out.println(" <BODY>");
out.println("您的IP地址为：<b>"+ip+"</b><br/>");
out.println(" </BODY>");
out.println("</HTML>");
out.flush();
out.close();
}
} 展开
1个回答
展开全部
192.168.1.110，而并不是客户端的真实IP。 request.getRemoteAddr（）的方法获取的IP实际上是代理服务器的地址，并不是客户端的IP地址。 于是可得出获得
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