Question

2(x-3)方+2(x方-1)=4x+1要过程

Answer 1

2（x-3）^2+2(x^2-1)=4x+1
展开得：4x^2-16x+15=0
所以 Δ=16^2-4×4×15=16
由二次函数的公式可得 x=(16+或-根号下16）/(2×4)=1.5 或2.5

Answer 2

解：2（x^2-6x+9)+2x^2-2=4x+1
2x^2-12x+9+2x^2-2=4x+1
4x^2-16x=-8
x^2-4x=-2
(x-2)^2=-2+4
x-2=±根号2
所以x=±根号2＋2
（“^”是平方）

Answer 3

2(x-3)方+2（x方-1）=4x+1
2（x方-6x+9)+2x方-2=4x+1
4x方-12x+16=4x+1
4x方-16x+16=1
4(x方-4x+4)=1
4(x-2)方=1
（x-2)方=1/4
x-2=±1/2
x=2.5，x=1.5

Answer 4

2(x方-6x+9）+2x方-2=4x+1
2x方-12x+18+2x方-2=4x+1
4x方-12x+16=4x+1
4x方-16x+15=0
(2x-5)(2x-3)=0
x=5/2(二分之五)或3/2(二分之三)

Answer 5

2(x²-6x+9)+2(x²-1)=4x+1
4x²-16x+15=0
(2x-3)(2x-5)=0
X=1.5或x=2.5