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z=(-1+√3i)^3-8i
let
z1 =-1+√3i
|z1| = 2
argz1= arctan(-√3) =2π/3
z1 =2[ cos(2π/3) + isin(2π/3) ]
z1^3 = 8[ cos(2π) + isin(2π) ]
= 8i
ie
z= 8i-8i =0
let
z1 =-1+√3i
|z1| = 2
argz1= arctan(-√3) =2π/3
z1 =2[ cos(2π/3) + isin(2π/3) ]
z1^3 = 8[ cos(2π) + isin(2π) ]
= 8i
ie
z= 8i-8i =0
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