Question

java简单问题，新手求助 (5分)

我主要是想试用一下正则表达式：

import java.io.*;
import java.util.*;
import java.math.*;
import java.util.regex.*;
public class Main
{
public static void main(String[]args)
{
Scanner cin=new Scanner(System.in);
String eg="\\w+@\\w+(\\w{2,3})*\\.\\w{2.3}";
while(cin.hasNext())
{
String str=cin.nextLine();
if(str.matches(eg))
{
System.out.println(str+"有效地址");
}
else
{
System.out.println("无效地址");
}
}
}
}

可是输入后回车，报出错误：

Exception in thread "main" java.util.regex.PatternSyntaxException: Unclosed counted closure near index 23
\w+@\w+(\w{2,3})*\.\w{2.3}
^
at java.util.regex.Pattern.error(Unknown Source)
at java.util.regex.Pattern.closure(Unknown Source)
at java.util.regex.Pattern.sequence(Unknown Source)
at java.util.regex.Pattern.expr(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.util.regex.Pattern.<init>(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.util.regex.Pattern.matches(Unknown Source)
at java.lang.String.matches(Unknown Source)
at Main.main(Main.java:15)

求前辈指点~

Answer 1

String eg="\\w+@\\w+(\\w{2,3})*\\.\\w{2.3}";改为String eg="\\w+@\\w+(\\w{2,3})*\\.\\w{2,3}";后面的｛2.3｝应为｛2,3｝

Answer 2

String eg="\\w+@\\w+(\\w{2,3})*\\.\\w{2.3}";
最后面逗号打成句号了w{2.3}

Answer 3

看到一个逗号，一个句号。。

Answer 4

2,3