x²-1/x²+2x+1 - x+1/x-1 求化简
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原式=[(x－1)(x＋1)]/[(x＋1)²]－(x＋1)/(x－1)
=(x－1)/(x＋1)－(x＋1)/(x－1)
=[(x－1)²－(x＋1)²]/[(x＋1)(x－1)]
=(－4x)/(x²－1)
=(x－1)/(x＋1)－(x＋1)/(x－1)
=[(x－1)²－(x＋1)²]/[(x＋1)(x－1)]
=(－4x)/(x²－1)
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(x²-1)/(x²+2x+1)-(x+1)/(x-1)
=(x+1)(x-1)/(x+1)²-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)²-(x+1)²]/[(x+1)(x-1)]
=-4x/(x²-1)
=(x+1)(x-1)/(x+1)²-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)²-(x+1)²]/[(x+1)(x-1)]
=-4x/(x²-1)
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别人跟快 谢谢
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=(x+1)(x-1)/(x+1)²-(x+1)/(x-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)²-(x+1)²]/(x+1)(x-1)
=(x-1+x+1)(x-1-x-1)/(x+1)(x-1)
=2x(-2)/(x+1)(x-1)
=-4x/(x²-1)
=(x-1)/(x+1)-(x+1)/(x-1)
=[(x-1)²-(x+1)²]/(x+1)(x-1)
=(x-1+x+1)(x-1-x-1)/(x+1)(x-1)
=2x(-2)/(x+1)(x-1)
=-4x/(x²-1)
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有人先了 谢谢支持
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