求数学高手帮忙做几道数学题 谢谢
1.已知tanα=-1,则2sin²α-cos²α分之1+2sinα×cosα=2.cos750°×sin(-690°)=3.已知sinα+cosα=...
1.已知tanα=-1,则2sin²α-cos²α分之1+2sinα×cosα=
2.cos750°×sin(-690°)=
3.已知sinα+cosα=1/2,则sinα×cosα=
4.已知sinα×cosα=1/8,且sinα>cosα,则cosα-sinα=
5.sin210°= tan600°= 根号下1-sin²1190°=
6.若cos(π+α)=-1/2,则cos(3π+α)=
7.若sin(-α-π)=1/3,则sin(9π+α)=
8.根号下1+tan²(-3π/6)-2tan(-43π/6)=
9.若cos(-100°)=a,则tan80°=
10.已知sin(π-α)=-2/3,α∈(-π/2,0),求tan(2π-α)的值 (要过程) 展开
2.cos750°×sin(-690°)=
3.已知sinα+cosα=1/2,则sinα×cosα=
4.已知sinα×cosα=1/8,且sinα>cosα,则cosα-sinα=
5.sin210°= tan600°= 根号下1-sin²1190°=
6.若cos(π+α)=-1/2,则cos(3π+α)=
7.若sin(-α-π)=1/3,则sin(9π+α)=
8.根号下1+tan²(-3π/6)-2tan(-43π/6)=
9.若cos(-100°)=a,则tan80°=
10.已知sin(π-α)=-2/3,α∈(-π/2,0),求tan(2π-α)的值 (要过程) 展开
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