Question

已知3x²-x-4=0,求(x-1)(2x-1)+(x+1)²+1的值

Answer 1

3x²-x-4=0
（x+1)(3x-4)=0
得出，x= -1,x=4/3
x=-1时
(x-1)(2x-1)+(x+1)²+1
=(-1-1)(-1*2-1)+(-1+1)²+1
=2*(-3)+0+1
=-5
x=4/3
(x-1)(2x-1)+(x+1)²+1
=2x ²-3x+1+x ²+2x+1+1
=3x ²-x+3
=3(4/3) ²-4/3+3
=7

Answer 2

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Answer 3

3x²-x-4=0
3x²-x=4

(x-1)(2x-1)+(x+1)²+1
=2x^2-3x+1+x^2+2x+2
=3x^2-x+3
=4+3
=7

Answer 4

(3x-4)(x+1)=0;
x=4/3或x=-1；
(x-1)(2x-1)+(x+1)²+1
=2x²-x-2x+1+x²+2x+1+1
=3x²-x+3
=7

Answer 5

(x-1)(2x-1)+(x+1)²+1=2x²-3x+1+x²+2x+1+1=3x²-x+3=4+3=7