分解因式:(a+3b)的三次方-a的三次方-27 乘b的三次方 ②x的四次方+x的三次方+6乘以x的平方+5x+5
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①=(a+3b)³-(a³+(3b)³)
=(a+3b)³-(a+3b)(a²-ab+9b²)
=(a+3b){(a+3b)²-(a²+6ab+9b²)+7ab}这步是再(a²-ab+9b²)里面加了一个6ab 里所应当-7ab
=(a+3b){(a+3b)²-(a+3b)²+7ab}
=7ab(a+3b)
② x^4+x³+6x²+5x+5
=x^4+x³+5x²+x²+5x+5
=(x^4+5x²)+(x³+5x)+(x²+5)
=x²(x²+5)+x(x²+5)+(x²+5)
=(x²+5)(x²+x+1)
=(a+3b)³-(a+3b)(a²-ab+9b²)
=(a+3b){(a+3b)²-(a²+6ab+9b²)+7ab}这步是再(a²-ab+9b²)里面加了一个6ab 里所应当-7ab
=(a+3b){(a+3b)²-(a+3b)²+7ab}
=7ab(a+3b)
② x^4+x³+6x²+5x+5
=x^4+x³+5x²+x²+5x+5
=(x^4+5x²)+(x³+5x)+(x²+5)
=x²(x²+5)+x(x²+5)+(x²+5)
=(x²+5)(x²+x+1)
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(a+3b)³-a³-27b³
=(a+3b)³-(a³+27b³)
=(a+3b)³-[a³+(3b)³]
=(a+3b)³-(a+3b)(a²-3ab+9b²)
=(a+3b)[(a+3b)²-(a²-3ab+9b²)]
=(a+3b)(a²+6ab+9b²-a²+3ab-9b²)
=(a+3b)×9ab
=9ab(a+3b)
x^4+x³+6x²+5x+5
=(x^4+x³+x²)+(5x²+5x+5)
=x²(x²+x+1)+5(x²+x+1)
=(x²+x+1)(x²+5)
=(a+3b)³-(a³+27b³)
=(a+3b)³-[a³+(3b)³]
=(a+3b)³-(a+3b)(a²-3ab+9b²)
=(a+3b)[(a+3b)²-(a²-3ab+9b²)]
=(a+3b)(a²+6ab+9b²-a²+3ab-9b²)
=(a+3b)×9ab
=9ab(a+3b)
x^4+x³+6x²+5x+5
=(x^4+x³+x²)+(5x²+5x+5)
=x²(x²+x+1)+5(x²+x+1)
=(x²+x+1)(x²+5)
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