Question

解方程：(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)、、x=？？？求过程

Answer 1

解：
(x-4)/(x-5) -(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)
(x-4)/(x-5)+(x-8)/(x-9)=(x-5)/(x-6)+(x-7)/(x-8)
(x-5+1)/(x-5)+(x-9+1)/(x-9)=(x-6+1)/(x-6)+(x-8+1)/(x-8)
1/(x-5)+1/(x-9) +2=1/(x-6) +1/(x-8)+2
1/(x-5)+1/(x-9)=1/(x-6)+1/(x-8)
[(x-5)+(x-9)]/[(x-5)(x-9)]=[(x-6)+(x-8)]/[(x-6)(x-8)]
(2x-14)/(x²-14x+45)=(2x-14)/(x²-14x+48)
分母x²-14x+45恒≠x²-14x+48，要等式成立，只有分子=0
2x-14=0
x=7
代入分式方程检验，分母均≠0，x=7是分式方程的解。

x=7

Answer 2

直接按步骤来计算

Answer 3

1/﹙x－5﹚－1/﹙x－6﹚＝1/﹙x－8﹚－1/﹙x－9﹚
﹙x－5﹚﹙x－6﹚＝﹙x－8﹚﹙x－9﹚
x＝7

Answer 4

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