Question

如何用switch语句编写四则运算？要求输入运算符跟两个数字，直接输出结

如何用switch语句编写四则运算？要求输入运算符跟两个数字，直接输出结果= =

Answer 1

#include <stdio.h>
int main(int argc, char **argv)
{
double operand1;
double operand2;
char operator[1];
while (1)
{
printf("输入数值和运算符(数值->运算符->数值):");
scanf("%lf%c%lf", &operand1,&operator[0], & operand2);
switch (operator[0])
{
case '+': printf("%.2lf\n", operand1 + operand1);
break;
case '-': printf("%.2lf\n", operand1 - operand2);
break;
case '*': printf("%.2f\n", operand1 * operand2);
break;
case '/': if (operand2 == 0)
{
printf("invalid operand!\n");
break;
}
printf("%.2f\n", operand1 / operand2);
break;
default: printf("unknown operator\n");
break;
}
}
}

Answer 2

#include#includeintmain(){intnumOne=0;intnumTwo=0;intresult=0;charoperator;cin>>a;cin>>b;cin>>operator;switch(operator){case"+":sum=numOne+numTwo;break;case"-":sum=numOne-numTwo;break;case"*":sum=numOne*numTwo;break;case"/":sum=numOne/numTwo;break;default:break;}cout<<"Theresultis:"<