Question

编写JAVA程序，实现输出1--100之间所有不能被7整除的数，并求和 　　要求：每输出4个数据换行显示

Answer 1

/**
* 输出1--100之间所有不能被7整除的数，并求和 　　要求：每输出4个数据换行显示
*/
public static void main(String[] args) {
int sum=0; //和
int j=0;
//已知次数，用for循环解决该问题
for (int i = 1; i <=100; i++)
{
if(i%7==0)
{
continue;
}else
{
System.out.print(" "+i);
}
j++;
if(j%4==0)

{
System.out.println("");
}

sum=sum+i;
}
System.out.println("和为："+sum);
}
}

Answer 2

public class t2
{
public static void main(String []args)
{
int count=0;
for(int i=1;i<=100;i++)
{
if(i%7!=0)
{
System.out.print(i+" ");
count++;
}
if(count%4==0)
System.out.println("");
}
}
}

Answer 3

public class Div {
public static void main(String[] args) {
for (int i = 1, count = 0; i <= 100; i++) {
if (count == 4) {
System.out.println();
count = 0;
}
if (i % 7 != 0) {
count++;
System.out.print(i + "\t");
}
}
}
}

Answer 4

给个代码你
public void test() {
int num = 0;
int sum = 0;
for(int i = 0;i <= 100;i ++) {
if(i % 7 != 0) {
num ++;
sum += i;
System.out.print(i + "\t");
if(num % 4 == 0)
System.out.println();
}
}
System.out.println();
System.out.println("sum="+sum);
}

Answer 5

package com.gem.test1;
class Array{
public void print() {
int i[]=new int[100];
int count=0;int sum=0;
for (int j = 0; j < i.length; j++) {
i[j]=j;
if((i[j]%7)==0){
count++;
sum+=i[j];
System.out.print(i[j]+"\t");
if (count%4==0) {
System.out.println();
}
}
}
System.out.print(sum);
}
}
public class ArrayDemo {
public static void main(String[] args) {
Array arr=new Array();
arr.print();
}
}
结果：
0 7 14 21
28 35 42 49
56 63 70 77
84 91 98 735