Question

计算下列两道题

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Answer 1

（1）原式=√12 - √3 x （2 - √3）/（4-3）=2√3 - 2√3 + 3=3
（2）原式=（3+2-2√6）+ 4（√6 - 2）/（6-2）=5-2√6 +√6 -2=3-√6

Answer 2

解：（1）√12-√3/(2+√3)
=√12-√3(2-√3)/(2+√3)(2-√3)
=√12-2√3+3
=2√3-2√3+3
=3
(2) (√3-√2)² +4/(√6+2)
=3-2√6+2+4(√6-2)/(√6+2)(√6-2)
=5-2√6+4(√6-2)/2
=5-2√6+2(√6-2)
=5-2√6+2√6-4
=1