Question

如何用java读取客户端上传的rar文件

Answer 1

直接通过工具类进行解压或者压缩文件即可。

import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.Closeable;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;

/**
*
* @author gdb
*/
public class ZipUtilAll {
public static final int DEFAULT_BUFSIZE = 1024 * 16;

/**
* 解压Zip文件
*
* @param srcZipFile
* @param destDir
* @throws IOException
*/
public static void unZip(File srcZipFile, String destDir) throws IOException
{
ZipFile zipFile = new ZipFile(srcZipFile);
unZip(zipFile, destDir);
}

/**
* 解压Zip文件
*
* @param srcZipFile
* @param destDir
* @throws IOException
*/
public static void unZip(String srcZipFile, String destDir) throws IOException
{
ZipFile zipFile = new ZipFile(srcZipFile);
unZip(zipFile, destDir);
}

/**
* 解压Zip文件
*
* @param zipFile
* @param destDir
* @throws IOException
*/
public static void unZip(ZipFile zipFile, String destDir) throws IOException
{
Enumeration<? extends ZipEntry> entryEnum = zipFile.entries();
ZipEntry entry = null;
while (entryEnum.hasMoreElements()) {
entry = entryEnum.nextElement();
File destFile = new File(destDir + entry.getName());
if (entry.isDirectory()) {
destFile.mkdirs();
}
else {
destFile.getParentFile().mkdirs();
InputStream eis = zipFile.getInputStream(entry);
System.out.println(eis.read());
write(eis, destFile);
}
}
}

/**
* 将输入流中的数据写到指定文件
*
* @param inputStream
* @param destFile
*/
public static void write(InputStream inputStream, File destFile) throws IOException
{
BufferedInputStream bufIs = null;
BufferedOutputStream bufOs = null;
try {
bufIs = new BufferedInputStream(inputStream);
bufOs = new BufferedOutputStream(new FileOutputStream(destFile));
byte[] buf = new byte[DEFAULT_BUFSIZE];
int len = 0;
while ((len = bufIs.read(buf, 0, buf.length)) > 0) {
bufOs.write(buf, 0, len);
}
} catch (IOException ex) {
throw ex;
} finally {
close(bufOs, bufIs);
}
}

/**
* 安全关闭多个流
*
* @param streams
*/
public static void close(Closeable... streams)
{
try {
for (Closeable s : streams) {
if (s != null)
s.close();
}
} catch (IOException ioe) {
ioe.printStackTrace(System.err);
}
}

/**
* @param args
* @throws java.lang.Exception
*/
public static void main(String[] args) throws Exception
{
// unZip(new File(ZipDemo.class.getResource("D:/123/HKRT-B2B.zip").toURI()), "D:/123/");
unZip("D:/123/123.zip", "D:/123/");
// new File();
}
}

Answer 2

压缩文件的处理和普通的一样，先上传到服务器，然后通过java的解压缩方式将文件解压出来，再进行读取