高数的一道题,急求!!!!!!!!!!!!!!!!!!!sos
2个回答
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解:
X(n)·[1-1/2²]
=[1-(1/2²)]·[1+(1/2²)]·[1+(1/2^4)]········[1+(1/2^2n)]
=[1-(1/2^4)]·[1+(1/2^4)]········[1+(1/2^2n)]
......
=[1-(1/2^2n)]·[1+(1/2^2n)]
=1-(1/2^4n)
∴
X(n)
=[1-(1/2^4n)]/[1-1/2²]
=(4/3)·[1-(1/2^4n)]
X(n)·[1-1/2²]
=[1-(1/2²)]·[1+(1/2²)]·[1+(1/2^4)]········[1+(1/2^2n)]
=[1-(1/2^4)]·[1+(1/2^4)]········[1+(1/2^2n)]
......
=[1-(1/2^2n)]·[1+(1/2^2n)]
=1-(1/2^4n)
∴
X(n)
=[1-(1/2^4n)]/[1-1/2²]
=(4/3)·[1-(1/2^4n)]
追问
不对吧。。。。2的次方数是2.4.6.8....而你这个削的是2.4.8.16啊
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