Question

Y=3x^2-6X+2配方

Answer 1

解答：
y=3x²-6x+2
在3x²-6x提取3
即3x²-6x=3﹙x²-2x﹚
再在x²-2x中+1
3﹙x²-2x+1﹚
因为多+了3
∴相对原式3﹙x²-2x﹚多3
所以要减去3
所以3﹙x²-2x﹚=3﹙x²-2x+1﹚-3=3（x-1）² -3
∵y=3x²-6x+2
3x²-6x=3（x-1）² -3
∴y=3（x-1）² -3+2=3（x-1）² -1

Answer 2

这是个函数，只有当Y=0时，才是方程。这时我们才把解X的过程叫做求这个一3x^2-6x+2=0 等式两边同除以3得x^2-2x+2/3=0 配方得（x-1）^2-

Answer 3

y=3(x²-2x)+2
=3(x²-2x+1-1)+2

=3(x²-2x+1)-3+2

=3(x-1)²-1

Answer 4

y=3(x²-2x)+2=3(x-1)²-1

Answer 5

y=3(x²-2x)+2=3(x-1)²-1