Question

不等式logx(2x+1)>logx(3-x)的解集

Answer 1

0<x<1时，2X+1<3-x，则推出x<(2/3)，则0<x<(2/3)
当X>1,x>(2/3),则x>1
{x/0<x<(2/3)∪X>1}

Answer 2

2x＋1＞0 x＞-1/2
3-x＞0 x＜3
x＞0且x≠1
x∈﹙0,1﹚∪﹚﹙1,3﹚
logx(2x+1)>logx(3-x)
logx(2x+1)－logx(3-x)＞0
㏒x﹙2x-1/3-x﹚＞㏒x1
∴2x-1/3-x＞1
2x-1＞3-x
x＞4/3
∴x∈﹙4/3,3﹚