数学学霸帮忙，先化简，再求值，要过程，谢
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说明：^2——表示平方
[x^2/(x-1)-x-1]·(1-x)/(x+1)
=[x^2/(x-1)-(x+1)]·[-(x-1)/(x+1)]
=-[x^2-(x+1)(x-1)]/(x-1)·(x-1)/(x+1)
=-[x^2-(x^2-1)]/(x+1)
=-(x^2-x^2+1)/(x+1)
=-1/(x+1)
=-1/(√3-1+1)
=-1/√3
=-√3/3
[x^2/(x-1)-x-1]·(1-x)/(x+1)
=[x^2/(x-1)-(x+1)]·[-(x-1)/(x+1)]
=-[x^2-(x+1)(x-1)]/(x-1)·(x-1)/(x+1)
=-[x^2-(x^2-1)]/(x+1)
=-(x^2-x^2+1)/(x+1)
=-1/(x+1)
=-1/(√3-1+1)
=-1/√3
=-√3/3
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