Question

数学化简题

Answer 1

sin^2atana+cos^2acota-2sinacos(π-a)
=sin^3a/cosa+cos^3a/sina+2sinacosa
=(sin^4a+cos^4a+2sin^acos^a)/sinacosa
=(sin^2a+cos^2a)^2/sinacosa
=1/sinacosa
=2/2sinacosa
=2/sin2a

欢迎追问！

Answer 2

=(sinα)^3/cosα+(cosα)^3/sinα+2sinαcosα
=[(sinα)^4+(cosα)^4+2(sinα)^2*(cosα)^2]/sinαcosα
=[(sinα)^2+(cosα)^2]^2/sinαcosα
=1/sinαcosα

想了有一会来着，，同学，其实你的字应该还是不错的