Question

想向你请教一下Syntax error on token "int", @ expected这样的错误怎么改？谢谢了

public class Person {
private String name;
private int age;
public Person(String name,int age){
this.setName(name);
this.setAge(age);
}
public void setName(String name) {
if(name==null||name=="")
this.name="姓名未知";
else
this.name=name;
}
public String getName(){
return this.name;
}
public void setAge(int age) {
try{
if(age>0&&age<100)
this.age=age;
else
throw new Exception("年龄无效");
}
catch(Exception e){
System.out.println(e.toString());
}
public int getAge(){
return this.age;
}
public String toString(){
return getName()+","+getAge()+"岁";
}
public int olderThen(Person p2){
return this.getAge()-p2.getAge();
}
public static void main(String[] args){
Person p1=new Person("小李子",36);
System.out.println(p1.toString());
Person p2=new Person("小贾",26);
System.out.println(p2.toString());
System.out.println(p1.getName()+"比"+p2.getName()+"大"+p1.olderThen(p2)+"岁");

}

}
}

Answer 1

public void setAge(int age) {
try{
if(age>0&&age<100)
this.age=age;
else
throw new Exception("年龄无效");
}
catch(Exception e){
System.out.println(e.toString());
}
这个方法结尾少了个 }

而在
public static void main(String[] args){
Person p1=new Person("小李子",36);
System.out.println(p1.toString());
Person p2=new Person("小贾",26);
System.out.println(p2.toString());
System.out.println(p1.getName()+"比"+p2.getName()+"大"+p1.olderThen(p2)+"岁");

}

}
}

这里多了个}